Answer : Using the case: nums[2, 1, 2] to run the above code with nums.sort(), you will see why the sorting is necessary. https://www.youtube.com/watch?v=XtJ-dpLmK4Y, This solution is for array contains duplicates numbers: temp.add(num[i]); GoodTecher LeetCode Tutorial 90. ... Subsets II (Medium) Given a collection of integers that might contain duplicates, nums, return all possible subsets. So all subsets for this no-duplicate set can be easily constructed: num of subset (1 to 2^0) empty set is the first subset (2^0+1 to 2^1) add the first element into subset from (1) (2^1+1 to 2^2) add the second element into subset (1 to 2^1) Example: Note: Elements in a subset must be in non-descending order. leetcode. Approach 3: Lexicographic (Binary Sorted) Subsets. Description. Whenever you modify the result just check if the list exist in the result. 2) â¦ Note: Elements in a subset must be in non-descending order. } Array. The solution set must not contain duplicate subsets. The solution set must not contain duplicate subsets. Notice - Elements in a subset must be in non-descending order. //get existing sets Note: The solution set must not contain duplicate subsets. Leetcode 90 - Backtracking | Subsets II Nideesh Terapalli. Leetcode: Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. ... Subsets II (Medium) Given a collection of integers that might contain duplicates, nums, return all possible subsets. The idea of this solution is originated from Donald E. Knuth.. Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Move Zeros. tl;dr: Please put your code into a

`YOUR CODE`